1
GATE ME 2005
MCQ (Single Correct Answer)
+2
-0.6
A $$U$$-tube manometer with a small quantity of mercury is used to measure the static pressure difference between two locations $$A$$ and $$B$$ in a conical section through which an incompressible fluid flows. At a particular flow rate, the mercury column appears as shown in the figure. The density of mercury is $$13600$$ $$kg/{m^3}$$ and $$g = 9.81$$ $$m/{s^2}.$$ Which of the following is correct? GATE ME 2005 Fluid Mechanics - Fluid Dynamics Question 39 English
A
Flow direction is $$A$$ to $$B$$ & $${P_A} - {P_B} = 20\,kPa$$
B
Flow direction is $$B$$ to $$A$$ & $${P_A} - {P_B} = 1.4\,kPa$$
C
Flow direction is $$A$$ to $$B$$ & $${P_B} - {P_A} = 20\,kPa$$
D
Flow direction is $$B$$ to $$A$$ & $${P_B} - {P_A} = 1.4\,kPa$$
2
GATE ME 2005
MCQ (Single Correct Answer)
+2
-0.6
A venturimeter of $$20$$ $$mm$$ throat diameter is used to measure the velocity of water in a horizontal pipe of $$40$$ $$mm$$ diameter. If the pressure difference between the pipe and throat sections is found to be $$30$$ $$kPa$$ then, neglecting frictional losses, the flow velocity is
A
$$0.2$$ $$m/s$$
B
$$1$$ $$m/s$$
C
$$1.4$$ $$m/s$$
D
$$2.0$$ $$m/s$$
3
GATE ME 2005
MCQ (Single Correct Answer)
+2
-0.6
A leaf is caught in a whirlpool. At a given instant, the leaf is at a distance of $$120$$ $$m$$ from the centre of the whirlpool. The whirlpool can be described by the following velocitry distribution ;
$${V_r} = - \left( {{{60 \times {{10}^3}} \over {2\pi r}}} \right)m/s$$
and $${V_\theta } = - \left( {{{300 \times {{10}^3}} \over {2\pi r}}} \right)m/s.$$

Where $$r$$ (in meters) is the distance from the centre of the whirlpool . What will be the distance of the leaf from the centre when it has moved through half a revolution?

A
$$48$$ $$m$$
B
$$64$$ $$m$$
C
$$120$$ $$m$$
D
$$142$$ $$m$$
4
GATE ME 2005
MCQ (Single Correct Answer)
+1
-0.3
The velocity components in the $$x$$ and $$y$$ directions of a two dimensional potential flow are $$u$$ and $$v$$, respectively. Then $${{\partial u} \over {\partial y}}$$ is equal to
A
$${{\partial v} \over {\partial x}}$$
B
$$ - {{\partial v} \over {\partial x}}$$
C
$${{\partial v} \over {\partial y}}$$
D
$$ - {{\partial v} \over {\partial y}}$$
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