WB JEE 2017 | Definite Integration Question 63 | Mathematics

WB JEE 2017

MCQ (Single Correct Answer)

-0.25

The value of the integral $$\int_0^1 {{e^{{x^2}}}} dx$$

is less than 1

is greater than 1

is less than or equal to 1

lies in the closed interval [1, e]

WB JEE 2017

MCQ (Single Correct Answer)

-0.25

$$\int_0^{100} {{e^{x - [x]}}} dx$$ is equal to

$${{{e^{100}} - 1} \over {100}}$$

$${{{e^{100}} - 1} \over {e - 1}}$$

$$100(e - 1)$$

$${{e - 1} \over {100}}$$

WB JEE 2017

MCQ (Single Correct Answer)

-0.5

If $$f(x) = \int_{ - 1}^x {|t|} \,dt$$, then for any $$x \ge 0,\,f(x)$$ is equal to

$${1 \over 2}(1 - {x^2})$$

$$1 - {x^2}$$

$${1 \over 2}(1 + {x^2})$$

$$1 + {x^2}$$

WB JEE 2017

MCQ (Single Correct Answer)

-0.5

Let $$I = \int_0^{100\pi } {\sqrt {(1 - \cos 2x)} } \,dx$$, then

I = 0

I = 200$$\sqrt 2 $$

I = $$\pi$$$$\sqrt 2 $$

I = 100

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