1
WB JEE 2019
MCQ (Single Correct Answer)
+1
-0.25
Change Language
The value of $$\mathop {\lim }\limits_{x \to 0} {1 \over x}\left[ {\int\limits_y^a {{e^{{{\sin }^2}t}}dt - } \int\limits_{x + y}^a {{e^{{{\sin }^2}t}}dt} } \right]$$ is equal to
A
$${{e^{{{\sin }^2}y}}}$$
B
$${{e^{{2{\sin }}y}}}$$
C
e| sin y|
D
$${e^{\cos e{c^2}y}}$$
2
WB JEE 2019
MCQ (Single Correct Answer)
+1
-0.25
Change Language
The value of the integral $$\int\limits_{ - 1}^1 {\left\{ {{{{x^{2015}}} \over {{e^{|x|}}({x^2} + \cos x)}} + {1 \over {{e^{|x|}}}}} \right\}} dx$$ is equal to
A
0
B
1 $$-$$ e$$-$$1
C
2e$$-$$1
D
2(1 $$-$$ e$$-$$1)
3
WB JEE 2019
MCQ (Single Correct Answer)
+1
-0.25
Change Language
$$\mathop {\lim }\limits_{n \to \infty } {3 \over n}\left[ {1 + \sqrt {{n \over {n + 3}}} + \sqrt {{n \over {n + 6}}} + \sqrt {{n \over {n + 9}}} + ... + \sqrt {{n \over {n + 3(n - 1)}}} } \right]$$
A
does not exist
B
is 1
C
is 2
D
is 3
4
WB JEE 2018
MCQ (Single Correct Answer)
+1
-0.25
Change Language
If $$M = \int\limits_0^{\pi /2} {{{\cos x} \over {x + 2}}dx} $$, $$N = \int\limits_0^{\pi /4} {{{\sin x\cos x} \over {{{(x + 1)}^2}}}dx} $$, then the value of M $$-$$ N is
A
$$\pi$$
B
$${\pi \over 4}$$
C
$${2 \over {\pi - 4}}$$
D
$${2 \over {\pi + 4}}$$
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Medical
NEET
Graduate Aptitude Test in Engineering
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CBSE
Class 12