WB JEE 2021 | Application of Integration Question 18 | Mathematics

WB JEE 2021

MCQ (Single Correct Answer)

-0.25

The straight the through the origin which divides the area formed by the curves y = 2x $$-$$ x², y = 0 and x = 1 into two equal halves is

y = x

y = 2x

y = $${3 \over 2}$$ x

y = $${2 \over 3}$$ x

WB JEE 2021

MCQ (Single Correct Answer)

-0.5

The area bounded by the parabolas $$y = 4{x^2},y = {{{x^2}} \over 9}$$ and the straight line y = 2 is

$${{20\sqrt 2 } \over 3}$$ sq. unit

$$10\sqrt 5 $$ sq. unit

$${{10\sqrt 3 } \over 7}$$ sq. unit

$$10\sqrt 2 $$ sq. unit

WB JEE 2020

MCQ (Single Correct Answer)

-0.25

If $${x^2} + {y^2} = {a^2}$$, then $$\int\limits_0^a {\sqrt {1 + {{\left( {{{dy} \over {dx}}} \right)}^2}} dx = } $$

2$$\pi a$$

$$\pi a$$

$${1 \over 2}\pi a$$

$${1 \over 4}\pi a$$

WB JEE 2020

MCQ (Single Correct Answer)

-0.25

Area in the first quadrant between the ellipses x² + 2y² = a² and 2x² + y² = a² is

$${{{a^2}} \over {\sqrt 2 }}{\tan ^{ - 1}}{1 \over {\sqrt 2 }}$$

$${{3{a^2}} \over 4}{\tan ^{ - 1}}{1 \over 2}$$

$${{5{a^2}} \over 2}{\sin ^{ - 1}}{1 \over 2}$$

$${{9\pi {a^2}} \over 2}$$

WB JEE Subjects