1
TS EAMCET 2020 (Online) 10th September Evening Shift
MCQ (Single Correct Answer)
+1
-0

Two straight lines $3 x+4 y=5$ and $4 x-3 y=15$ intersect at the point $A$. The equations of the lines passing through $(1,2)$ and intersecting the given lines at $B$ and $C$ such that $A B=A C$ are

A

$x+4 y=9,4 x-y=2$

B

$9 x-2 y=5,2 x+9 y=20$

C

$6 x-y=4, x+6 y=13$

D

$7 x+y=9, x-7 y+13=0$

2
TS EAMCET 2020 (Online) 10th September Evening Shift
MCQ (Single Correct Answer)
+1
-0

The equation of a line making an angle $60^{\circ}$ with the line $x+y-3=0$ and passing through the point $(1,1)$ is

A

$(1+\sqrt{3}) x+(1-\sqrt{3}) y-2=0$

B

$2 x+y-3=0$

C

$\sqrt{3} x+(1-\sqrt{3}) y=1$

D

$\sqrt{3} x+(2+\sqrt{3}) y=2(1+\sqrt{3})$

3
TS EAMCET 2020 (Online) 10th September Evening Shift
MCQ (Single Correct Answer)
+1
-0

Let $P$ be the pair of lines represented by $2 x^2-5 x y+2 y^2+6 x-3 y=0$ and consider the following independent statements

(i) $\alpha$ is the $x$ coordinate of the point of intersection of the pair of lines $P$.

(ii) $\beta$ is the slope of one of the lines of $P$ passing through origin.

(iii) $\gamma$ is the constant term in the equation of the pair of angular bisectors of $P$.

Then,

A

$\beta<\gamma<\alpha$

B

$\alpha<\beta=\gamma$

C

$\alpha=\beta<\gamma$

D

$\gamma<\alpha<\beta$

4
TS EAMCET 2020 (Online) 10th September Evening Shift
MCQ (Single Correct Answer)
+1
-0

The combined equation of the diagonals of the parallelogram formed by the lines

$$ \left(7 x^2-4 x y+8 y^2\right)^2+(4 x-8 y-32)\left(7 x^2-4 x y+8 y^2\right)=0 $$

is

A

$x^2-x y+y^2+3 x-15 y=0$

B

$3 x^2-6 x y-2 y^2-15 x-17 y=0$

C

$3 x^2-5 x y-2 y^2-24 x-8 y=0$

D

$x^2-x y+y^2+15 x-12 y=0$

TS EAMCET Subjects

Browse all chapters by subject