The value of $$I = \int\limits_{ - \pi /2}^{\pi /2} {|\sin x|dx} $$ is

If $$I = \int\limits_0^1 {{{dx} \over {1 + {x^{\pi /2}}}}} $$, then

The value of $$\int\limits_{ - 2}^2 {(x\cos x + \sin x + 1)dx} $$ is

$$\int\limits_\pi ^{16\pi } {|\sin x|dx = } $$