1
TS EAMCET 2020 (Online) 14th September Morning Shift
MCQ (Single Correct Answer)
+1
-0

The solution of the differential equation $x \cos x \frac{d y}{d x}+(x \sin x+\cos x) y=1$ is

A

$x \sec x-y \tan x=C$

B

$x^2 y \cos x-\tan x=C$

C

$x y \sec x+y \tan x=C$

D

$x y \sec x-\tan x=C$

2
TS EAMCET 2020 (Online) 11th September Evening Shift
MCQ (Single Correct Answer)
+1
-0

If $\alpha$ and $\beta$ are respectively the order and degree of the differential equation for which $a x^2+b y^2=1$ is the general solution, then the eccentricity of the ellipse $\alpha x^2+\beta y^2=1$ is

A

$\frac{1}{\sqrt{2}}$

B

$\frac{1}{2}$

C

$\frac{1}{2 \sqrt{2}}$

D

$\frac{1}{\sqrt{2}+1}$

3
TS EAMCET 2020 (Online) 11th September Evening Shift
MCQ (Single Correct Answer)
+1
-0

The solution of the differential equation $x d y-y d x=\sqrt{x^2+y^2} d x$, given that $y=1$ when $x=\sqrt{3}$, is

A

$\left(x^2-y^2\right)^2=x^2+y^2$

B

$\left(x^2-y^2\right)^2=x^2+y^2$

C

$\left(x^2+y\right)^2=x^2-y^2$

D

$x^2-y=\left(x+y^2\right)^2$

4
TS EAMCET 2020 (Online) 11th September Evening Shift
MCQ (Single Correct Answer)
+1
-0

If the solution $y(x)$ of the differential equation $\sin x \frac{d y}{d x}+y \cos x=e^{2 x}, x \in(0, \pi)$ satisfies $y\left(\frac{\pi}{2}\right)=0$, then $y\left(\frac{\pi}{6}\right)=$

A

$e^{\pi / 3}+e^\pi$

B

$e^{\pi / 3}-e^\pi$

C

$e^\pi-e^{\pi / 3}$

D

$\frac{1}{2}\left(e^{\pi / 3}-e^\pi\right)$

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