WB JEE 2022 | Ellipse and Hyperbola Question 20 | Mathematics

WB JEE 2022

MCQ (More than One Correct Answer)

-0

The line y = x + 5 touches

the parabola y² = 20 x

the ellipse $$9{x^2} + 16{y^2} = 144$$

the hyperbola $${{{x^2}} \over {29}} - {{{y^2}} \over 4} = 1$$

the circle $${x^2} + {y^2} = 25$$

WB JEE 2020

MCQ (More than One Correct Answer)

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Consider a tangent to the ellipse $${{{x^2}} \over 2} + {{{y^2}} \over 1} = 1$$ at any point. The locus of the mid-point of the portion intercepted between the axes is

$${{{x^2}} \over 2} + {{{y^2}} \over 4} = 1$$

$${{{x^2}} \over 4} + {{{y^2}} \over 2} = 1$$

$${1 \over {3{x^2}}} + {1 \over {4{y^2}}} = 1$$

$${1 \over {2{x^2}}} + {1 \over {4{y^2}}} = 1$$

WB JEE 2019

MCQ (More than One Correct Answer)

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Equation of a tangent to the hyperbola 5x² $$-$$ y² = 5 and which passes through an external point (2, 8) is

3x $$-$$ y + 2 = 0

3x + y $$-$$ 14 = 0

23x $$-$$ 3y $$-$$ 22 = 0

3x $$-$$ 23y + 178 = 0

WB JEE 2018

MCQ (More than One Correct Answer)

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A hyperbola, having the transverse axis of length 2sin$$\theta$$ is confocal wit6h the ellipse 3x² + 4y² = 12. Its equation is

x²sin²$$\theta$$ $$-$$ y²cos²$$\theta$$ = 1

x²cosec²$$\theta$$ $$-$$ y²sec²$$\theta$$ = 1

(x² + y²)sin²$$\theta$$ = 1 + y²

x²cosec²$$\theta$$ = x² + y² + sin²$$\theta$$

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Chemistry

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