1
TS EAMCET 2023 (Online) 12th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

The equations of common tangents to the parabola $y^2=16 x$ and the circle $x^2+y^2=8$ are

A
$y=x+2, y=x-2$
B
$y=x+1, y=x-2$
C
$y=2 x+4, y=-2 x+4$
D
$y=x+4, y=-x-4$
2
TS EAMCET 2023 (Online) 12th May Morning Shift
MCQ (Single Correct Answer)
+1
-0
If two circles $x^2+y^2-6 x-6 y+13=0$ and $x^2+y^2-8 y+9=0$ intersect at $A$ and $B$, then the focus of the parabola whose directrix is the line $A B$ and vertex is the point $s(a, b)$ is
A
$\left(\frac{3}{5}, \frac{1}{5}\right)$
B
$\left(-\frac{3}{5}, \frac{1}{5}\right)$
C
$\left(-\frac{3}{5},-\frac{1}{5}\right)$
D
$\left(\frac{3}{5},-\frac{1}{5}\right)$
3
TS EAMCET 2023 (Online) 12th May Morning Shift
MCQ (Single Correct Answer)
+1
-0
Two tangents are drawn from the point $(-1,-2)$ to the parabola $y^2=4 x$. If $\theta$ is the angle between these tangents, then $\tan \theta=$
A
$\frac{\pi}{4}$
B
$\frac{\pi}{2}$
C
$\frac{\pi}{3}$
D
$\frac{\pi}{6}$
4
TS EAMCET 2022 (Online) 20th July Evening Shift
MCQ (Single Correct Answer)
+1
-0

The equation of the given curve is $x^2-4 x+4 y-8=0$. Match the following

$$ \begin{array}{lll} \hline & \text { List I } & \text { List II } \\ \hline \text { (A) } & \text { Focus } & \text { (I) }(4,2) \\ \hline \text { (B) } & \text { Vertex } & \text { (II) }(3,2) \\ \hline \text { (C) } & \begin{array}{l} \text { One end of the } \\ \text { latusrectum } \end{array} & \text { (III) }(2,3) \\ \hline \text { (D) } & \begin{array}{l} \text { point of intersection of the } \\ \text { axis and directrix } \end{array} & \text { (IV) }(2,4) \\ \hline & & \text { (V) }(2,2) \\ \hline \end{array} $$

$$ \text { The correct match is } $$

A
A B C D
II III I IV
B
A B C D
IV III I V
C
A B C D
V III IV I
D
A B C D
V III I IV

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