WB JEE 2008 | Parabola Question 7 | Mathematics

WB JEE 2008

MCQ (Single Correct Answer)

-0.25

The equation of the ellipse having vertices at ($$\pm$$ 5, 0) and foci ($$\pm$$ 4, 0) is

$${{{x^2}} \over {25}} + {{{y^2}} \over {16}} = 1$$

$$9{x^2} + 25{y^2} = 225$$

$${{{x^2}} \over 9} + {{{y^2}} \over {25}} = 1$$

$$4{x^2} + 5{y^2} = 20$$

WB JEE 2008

MCQ (Single Correct Answer)

-0.25

The latus rectum of an ellipse is equal to one-half of its minor axis. The eccentricity of the ellipse is

$${1 \over {\sqrt 6 }}$$

$${{\sqrt 3 } \over 2}$$

$${{\sqrt 3 } \over 4}$$

$${1 \over 2}$$

WB JEE 2009

MCQ (Single Correct Answer)

-0.25

The coordinates of the focus of the parabola described parametrically by x = 5t² + 2, y = 10t + 4 are

(7, 4)

(3, 4)

(3, $$-$$4)

($$-$$7, 4)

WB JEE 2010

MCQ (Single Correct Answer)

-0.25

If t₁ and t₂ be the parameters of the end points of a focal chord for the parabola y² = 4ax, then which one is true?

t₁t₂ = 1

$${{{t_1}} \over {{t_2}}} = 1$$

t₁t₂ = $$-$$1

t₁ + t₂ = $$-$$1

WB JEE Subjects