1
WB JEE 2008
MCQ (Single Correct Answer)
+1
-0.25

The equation of the circle which passes through the points of intersection of the circles $${x^2} + {y^2} - 6x = 0$$ and $${x^2} + {y^2} - 6y = 0$$, and has its centre at $$\left( {{3 \over 2},{3 \over 2}} \right)$$ is

A
$${x^2} + {y^2} + 3x + 3y + 9 = 0$$
B
$${x^2} + {y^2} + 3x + 3y = 0$$
C
$${x^2} + {y^2} - 3x - 3y = 0$$
D
$${x^2} + {y^2} - 3x - 3y + 9 = 0$$
2
WB JEE 2008
MCQ (Single Correct Answer)
+1
-0.25

The equation $$(x - {x_1})(x - {x_2}) + (y - {y_1})(y - {y_2}) = 0$$ represents a circle whose centre is

A
$$\left( {{{{x_1} - {x_2}} \over 2},{{{y_1} - {y_2}} \over 2}} \right)$$
B
$$\left( {{{{x_1} + {x_2}} \over 2},{{{y_1} + {y_2}} \over 2}} \right)$$
C
$$({x_1},{y_1})$$
D
$$({x_2},{y_2})$$
3
WB JEE 2008
MCQ (Single Correct Answer)
+1
-0.25

The circles $${x^2} + {y^2} + 6x + 6y = 0$$ and $${x^2} + {y^2} - 12x - 12y = 0$$

A
cut orthogonally
B
touch each other internally
C
intersect in two points
D
touch each other externally
4
WB JEE 2008
MCQ (Single Correct Answer)
+1
-0.25

The locus of the centres of the circles which touch both the axes is given by

A
$${x^2} - {y^2} = 0$$
B
$${x^2} + {y^2} = 0$$
C
$${x^2} - {y^2} = 1$$
D
$${x^2} + {y^2} = 1$$
WB JEE Subjects
Physics
Mechanics
Electricity
Optics
Modern Physics
Chemistry
Physical Chemistry
Inorganic Chemistry
Organic Chemistry
Mathematics
Algebra
Trigonometry
Coordinate Geometry
Calculus
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