1

WB JEE 2008

MCQ (Single Correct Answer)

+1

-0.25

The equation of the circle which passes through the points of intersection of the circles $${x^2} + {y^2} - 6x = 0$$ and $${x^2} + {y^2} - 6y = 0$$, and has its centre at $$\left( {{3 \over 2},{3 \over 2}} \right)$$ is

2

WB JEE 2008

MCQ (Single Correct Answer)

+1

-0.25

The equation $$(x - {x_1})(x - {x_2}) + (y - {y_1})(y - {y_2}) = 0$$ represents a circle whose centre is

3

WB JEE 2008

MCQ (Single Correct Answer)

+1

-0.25

The circles $${x^2} + {y^2} + 6x + 6y = 0$$ and $${x^2} + {y^2} - 12x - 12y = 0$$

4

WB JEE 2008

MCQ (Single Correct Answer)

+1

-0.25

The locus of the centres of the circles which touch both the axes is given by

Questions Asked from Circle (MCQ (Single Correct Answer))

Number in Brackets after Paper Indicates No. of Questions

WB JEE Subjects

Physics

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Units & Measurements Vector Algebra Motion Laws of Motion Circular Motion Work Power & Energy Center of Mass Rotational Motion Properties of Matter Heat and Thermodynamics Simple Harmonic Motion Waves Gravitation

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Some Basic Concepts of Chemistry Atomic Structure Redox Reaction Gaseous State Chemical Equilibrium Liquid Solution Ionic Equilibrium Thermodynamics Chemical Kinetics Radioactivity and Nuclear Chemistry Electrochemistry Solid State Surface Chemistry

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