WB JEE 2009 | Circle Question 5 | Mathematics

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WB JEE 2009

MCQ (Single Correct Answer)

-0.25

The equation of the chord of he circle $${x^2} + {y^2} - 4x = 0$$ whose midpoint is (1, 0) is

y = 2

y = 1

x = 2

x = 1

WB JEE 2009

MCQ (Single Correct Answer)

-0.25

The circles x² + y² $$-$$ 10x + 16 = 0 and x² + y² = a² intersect at two distinct points if

a < 2

2 < a < 8

a > 8

a = 2

WB JEE 2009

MCQ (Single Correct Answer)

-0.25

For the two circles x² + y² = 16 and x² + y² $$-$$ 2y = 0 there is/are

one pair of common tangents

only one common tangent

three common tangents

no common tangent

WB JEE 2010

MCQ (Single Correct Answer)

-0.25

The straight line x + y $$-$$ 1 = 0 meets the circle x² + y² $$-$$ 6x $$-$$ 8y = 0 at A and B. Then the equation of the circle of which AB is a diameter is

$${x^2} + {y^2} - 2y - 6 = 0$$

$${x^2} + {y^2} + 2y - 6 = 0$$

$$2({x^2} + {y^2}) + 2y - 6 = 0$$

$$3({x^2} + {y^2}) + 2y - 6 = 0$$

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