The area of the quadrilateral formed by the lines $x+2 y+3=0,2 x+4 y+9=0, x-2 y+3=0$ and $3 x-6 y+11=0$

If $(-1,-1)$ is the point of intersection of the pair of lines $2 x^2+5 x y-3 y^2+2 g x+2 f y+c=0$. Then $g+f$

A straight line passing through a point $(3,2)$ cuts $X$ and $Y$ axes at the points $A$ and $B$ respectively. If a point $P$ divides $A B$ in the ratio $2: 3$, then the equation of the locus of point $P$ is

By shifting the origin to the point $(-1,2)$ through translation of axes, if $a x^2+2 h x y+b y^2+2 g x+2 f y+c=0$ is the transformed equation of $2 x^2-x y+y^2-3 x+4 y-5=0$, then $2(f+g+h)=$