The absolute maximum value of the function $f(x)=2 x^3-3 x^2-36 x+9$ defined on $[-3,3]$ is

The approximate value of $\sqrt[3]{28}$ rounded up to 3 decimal places is

$y=x^2$ is the given curve. Imagine that this curve is dragged along the positive $X$-axis to a distance of ' $a$ ' units. If the acute angle between the curves at two positions is $\theta$, then

If $x$ and $y$ are two positive integers such that $x+2 y=10$ and $x^2 y^3$ is maximum, then $x^2+2 y^3=$