One of the values of $(-32 i)^{\frac{2}{5}}$ is

$$ \sqrt{(-3+4 i)(8+6 i)}= $$

If $\left(\frac{\sqrt{3}+i}{\sqrt{3}-i}\right)^m=1,2022 < m < 2029$, then $m=$

If $1, \omega, \omega^2$ are the cube roots of unity, $n \in N$ and $n>2$ then the least value of $n$ such that $1+\omega$ is a root of $x^n-x=0$ is