1
TS EAMCET 2020 (Online) 11th September Morning Shift
MCQ (Single Correct Answer)
+1
-0

Let $X \sim B(n, p)$ with mean $\mu$ and variance $\sigma^2$. If $\mu=2 \sigma^2$ and $\mu+\sigma^2=3$, then $P(X \leq 3)=$

A

$15 / 16$

B

$2 / 3$

C

$14 / 17$

D

$1 / 3$

2
TS EAMCET 2020 (Online) 10th September Evening Shift
MCQ (Single Correct Answer)
+1
-0

If $A_1, A_2, \ldots, A_{15}$ are the events of a random experiment, then which one of the following is true?

A

$P\left(\bigcap_{i=1}^{15} A_i\right) \leq \sum_{i=1}^{15} P\left(A_i\right)-15$

B

$P\left(\bigcap_{i=1}^{15} A_i\right) \geq \sum_{i=1}^{15} P\left(A_i\right)-14$

C

$P\left(\bigcup_{i=1}^{15} A_i\right) \geq \sum_{i=1}^{15} P\left(A_i\right)$

D

$$ P\left(\bigcup_{i=1}^{15} A_i\right) < \sum_{i=1}^{15} P\left(A_i\right)-\sum_{1 \leq i < j<15} P\left(A_i \cap A_j\right) $$

3
TS EAMCET 2020 (Online) 10th September Evening Shift
MCQ (Single Correct Answer)
+1
-0

In an examination there are four Yes/No type of questions. The probability that the answer by the student to a question without guess to be correct is $2 / 3$. The probability that a student guesses a correct answer is $1 / 2$. A student writes the examination either by without guessing answers to all the 4 questions or by guessing answers to all 4 questions. The probability that he attempt the exam by guessing answers to all questions is $3 / 7$. Given that a student answered at least 3 questions correctly, the probability that he answered all the questions without guessing is

A

$\frac{13}{15}$

B

$\frac{405}{1429}$

C

$\frac{1024}{1429}$

D

$\frac{2}{15}$

4
TS EAMCET 2020 (Online) 10th September Evening Shift
MCQ (Single Correct Answer)
+1
-0

Four boxes $A, B, C$ and $D$ contain 5000, 3000, 2000 and 1000 fuses respectively. The percentages of defective fuses in these boxes are $3 \%, 2 \%, 1 \%$ and $0.5 \%$ respectively. If a fuse selected at random from one of the boxes is found to be defective, then the probability that it has come from box $D$ is

A

$\frac{1}{13}$

B

$\frac{4}{65}$

C

$\frac{1}{65}$

D

$\frac{2}{13}$

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