1
TS EAMCET 2020 (Online) 10th September Evening Shift
MCQ (Single Correct Answer)
+1
-0

Let $f:[2,5] \rightarrow \mathbf{R}$ be a differentiatiable function and $\frac{f(5)}{f(2)}=1$. If there is a $c \in(2,5)$ such that $c f^{\prime}(c)=2 f(c)-2 c^3$, then $f(x)=$

A

$-2 x^3+\frac{78}{7} x^2$

B

$x^3-8 x^2+17 x-10$

C

$x^3-6 x^2+3 x+10$

D

$x^3-7 x^2+10 x$

2
TS EAMCET 2020 (Online) 10th September Evening Shift
MCQ (Single Correct Answer)
+1
-0

Let $f:[2,5] \rightarrow \mathbf{R}$ be a differentiatiable function and $\frac{f(5)}{f(2)}=1$. If there is a $c \in(2,5)$ such that $c f^{\prime}(c)=2 f(c)-2 c^3$, then $f(x)=$

A

$-2 x^3+\frac{78}{7} x^2$

B

$x^3-8 x^2+17 x-10$

C

$x^3-6 x^2+3 x+10$

D

$x^3-7 x^2+10 x$

3
TS EAMCET 2020 (Online) 10th September Evening Shift
MCQ (Single Correct Answer)
+1
-0

The differential equation for which $y=a x^2+b x+c$ is the general solution is

A

$\frac{d^4 y}{d x^4}=0$

B

$\frac{d^3 y}{d x^3}=0$

C

$\frac{d^5 y}{d x^5}=0$

D

$\frac{d^3 y}{d x^3}+\frac{d^4 y}{d x^4}=0$

4
TS EAMCET 2020 (Online) 10th September Evening Shift
MCQ (Single Correct Answer)
+1
-0

The general solution of the differential equation

$(3 y-7 x+7) d x+(7 y-3 x+3) d y=0$ is

A

$(x-y+1)^2(x+y-1)^5=C$

B

$(x+y+1)^5(x-y-1)^2=C$

C

$(x-y-1)^2(x+y-1)^5=C$

D

$(x+y-1)^7=C$

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