1
TS EAMCET 2023 (Online) 13th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

Let $A B C$ be a triangle and $A=(1,2)$. If $x-3 y-5=0$ the and $x+5 y-9=0$ are the perpendicular bisectors of the sides $A B$ and $B C$ respectively, then the length of the side $A C$ is

A

$\sqrt{34}$

B

$2 \sqrt{26}$

C

$2 \sqrt{10}$

D

$4 \sqrt{2}$

2
TS EAMCET 2023 (Online) 13th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

Let $A(4,3,5), B(1,-2,1), C(3,2,1)$ be the vertices of a $\triangle A B C$. If the internal bisector of $\angle B A C$ meet the side $B C$ at $D$, then $C D=$

A

$\frac{\sqrt{5}}{4}$

B

$\frac{3 \sqrt{5}}{4}$

C

$2 \sqrt{5}$

D

$\frac{5 \sqrt{5}}{2}$

3
TS EAMCET 2023 (Online) 12th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

A line $L$ has intercepts $a$ and $b$ on the coordinate axes. When the coordinate axes are rotated through an angle $\alpha$ and keeping the origin fixed, the same line $L$ has intercepts $p$ and $q$ on the new axes. Then,

A
$a^2+b^2=p^2+q^2$
B
$a^2+p^2=b^2+q^2$
C
$\frac{1}{a^2}+\frac{1}{p^2}=\frac{1}{b^2}+\frac{1}{q^2}$
D
$\frac{1}{a^2}+\frac{1}{b^2}=\frac{1}{p^2}+\frac{1}{q^2}$
4
TS EAMCET 2023 (Online) 12th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

Two lines $L_1$ and $L_2$ passing through the point $P(1,2)$ cut the line $x+y=4$ at a distance of $\frac{\sqrt{6}}{3}$ units from $P$. Then, the angles made by $L_1, L_2$ with positive $X$-axis are

A
$\frac{\pi}{3}, \frac{\pi}{6}$
B
$\frac{\pi}{8}, \frac{3 \pi}{8}$
C
$\frac{\pi}{12}, \frac{5 \pi}{12}$
D
$\frac{\pi}{4}, \frac{\pi}{8}$

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