WB JEE 2024 | Logarithms Question 9 | Mathematics

WB JEE 2024

MCQ (Single Correct Answer)

-0.25

If $$\left(x^2 \log _x 27\right) \cdot \log _9 x=x+4$$ then the value of $$x$$ is

$$ -\frac{4}{3} $$

$$-$$2

$$ \frac{4}{3} $$

WB JEE 2022

MCQ (Single Correct Answer)

-0.5

If x satisfies the inequality $${\log _{25}}{x^2} + {({\log _5}x)^2} < 2$$, then x belongs to

$$\left( {{1 \over 5},5} \right)$$

$$\left( {{1 \over {25}},5} \right)$$

$$\left( {{1 \over 5},25} \right)$$

$$\left( {{1 \over {25}},25} \right)$$

WB JEE 2020

MCQ (Single Correct Answer)

-0.25

If 2 log(x + 1) $$ - $$ log(x² $$ - $$ 1) = log 2, then x =

only 3

$$ - $$1 and 3

only $$ - $$1

1 and 3

WB JEE 2019

MCQ (Single Correct Answer)

-0.25

If $$\log _2^6 + {1 \over {2x}} = {\log _2}\left( {{2^{{1 \over x}}} + 8} \right)$$, then the value of x are

$${1 \over 4},{1 \over 3}$$

$${1 \over 4},{1 \over 2}$$

$$-$$$${1 \over 4},{1 \over 2}$$

$${1 \over 3}, - {1 \over 2}$$

WB JEE Subjects