1
TS EAMCET 2023 (Online) 14th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

If $\alpha, \beta, \gamma$ are the roots of the equation $x^3+x^2+x+1=0$, then match the items of List I with those of List II

List - I List - II
(i) $$
\frac{1}{\alpha}+\frac{1}{\beta}+\frac{1}{\gamma}
$$
(a) -1
(ii) $$
\alpha^3+\beta^3+\gamma^3
$$
(b) -4
(iii) $$
\alpha^4+\beta^4+\gamma^4
$$
(c) 1
(iv) $$
(\alpha-\beta)^2+(\beta-\gamma)^2+(\gamma-\alpha)^2
$$
(d) 3
(e) 0

Then, the correct match is

A

(i) $\rightarrow \mathrm{a}$, (ii) $\rightarrow \mathrm{a}$, (iii) $\rightarrow \mathrm{d}$, (iv) $\rightarrow \mathrm{b}$

B

(i) $\rightarrow \mathrm{c}$, (ii) $\rightarrow \mathrm{a}$, (iii) $\rightarrow \mathrm{e}$, (iv) $\rightarrow \mathrm{b}$

C

(i) $\rightarrow \mathrm{a}$, (ii) $\rightarrow \mathrm{c}$, (iii) $\rightarrow \mathrm{d}$, (iv) $\rightarrow \mathrm{b}$

D

(i) → c, (ii) → a, (iii) → b, (iv) → e

2
TS EAMCET 2023 (Online) 14th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

If $i=\sqrt{-1}$, then $\operatorname{Arg}\left[\frac{(1+i)^{2025}}{(1-i)^{2022}}\right]=$

A

$\frac{-\pi}{4}$

B

$\frac{\pi}{4}$

C

$\frac{3 \pi}{4}$

D

$\frac{-3 \pi}{4}$

3
TS EAMCET 2023 (Online) 14th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

The locus of $z$ such that $\left|\frac{z-i}{z+i}\right|=2$, where $z=x+i y$, is

A

$3 x^2+3 y^2+10 y+3=0$

B

$3 x^2-3 y^2-10 y-3=0$

C

$3 x^2+3 y^2+10 y-3=0$

D

$x^2+y^2-5 y+3=0$

4
TS EAMCET 2023 (Online) 14th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

If $x_n=\cos \frac{\pi}{2^n}+i \sin \frac{\pi}{2^n}$, then $\prod_{n=1}^{\infty} x_n=$

A

0

B

1

C

-1

D

$i$

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