1
TS EAMCET 2022 (Online) 19th July Evening Shift
MCQ (Single Correct Answer)
+1
-0

Assertion (A) The curves $y^2=4 x$ and $x^2=-2 y$ intersect at $(1,2)$ orthogonally.

Reason (R) If the product of the slopes of the tangents drawn to two curves at their point of intersection is -1 , then the curves are said to cut each other orthogonally.

A

(A) is true, (R) is true and (R) is the correct explanation for (A).

B

(A) is true, (R) is true, but (R) is not the correct explanation for (A).

C

(A) is true but (R) is false.

D

(A) is false but (R) is true.

2
TS EAMCET 2022 (Online) 19th July Evening Shift
MCQ (Single Correct Answer)
+1
-0

Let $f(x)=\left\{\begin{array}{cc}1+6 x-3 x^2 & x \leq 1 \\ x+\log _2\left(b^2+7\right) & x>1\end{array}\right.$. Then, the set of all possible values of $b$ such that $f(1)$ is the maximum value of $f(x)$ is

A

$[-1,1]$

B

$[0,1]$

C

$[0,2]$

D

$[-1,0]$

3
TS EAMCET 2022 (Online) 19th July Morning Shift
MCQ (Single Correct Answer)
+1
-0

If $\theta$ is the acute angle between the curves $x^2+y^2=4$ and $y^2=3 x$, then $\tan \theta=$

A

$\frac{5}{\sqrt{3}}$

B

$\frac{\sqrt{3}}{4}$

C

$\frac{4}{\sqrt{3}}$

D

$\frac{\sqrt{3}}{5}$

4
TS EAMCET 2022 (Online) 19th July Morning Shift
MCQ (Single Correct Answer)
+1
-0

Let $\sqrt{3}$ be the radius and $\frac{\pi}{3}$ be the semi-vertical angle of the given cone. Then, the height of the right circular cylinder of maximum volume that can be inscribed in the given cone is

A

3

B

$\frac{\sqrt{3}}{2}$

C

$\frac{2}{\sqrt{3}}$

D

$\frac{1}{3}$

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