1
TS EAMCET 2022 (Online) 20th July Morning Shift
MCQ (Single Correct Answer)
+1
-0

$$ \frac{1}{\sin 250^{\circ}}+\frac{\sqrt{3}}{\cos 290^{\circ}}= $$

A

$\frac{1}{\sqrt{3}}$

B

4

C

$\frac{4}{\sqrt{3}}$

D

1

2
TS EAMCET 2022 (Online) 20th July Morning Shift
MCQ (Single Correct Answer)
+1
-0

If $A+B+C=\frac{\pi}{2}$, then $\sqrt{2} \cos \left(\frac{\pi}{4}-A\right)$

$$ +\sqrt{2} \cos \left(\frac{\pi}{4}-B\right)+\sqrt{2} \cos \left(\frac{\pi}{4}-C\right)+1= $$

A

$4 \sqrt{2} \cos \frac{A}{2} \cos \frac{B}{2} \cos \frac{C}{2}$

B

$4 \cos \frac{A}{2} \cos \frac{B}{2} \cos \frac{C}{2}$

C

$4 \sin \frac{A}{2} \sin \frac{B}{2} \cos \frac{C}{2}$

D

$4 \sqrt{2} \sin \frac{A}{2} \sin \frac{B}{2} \cos \frac{C}{2}$

3
TS EAMCET 2022 (Online) 20th July Morning Shift
MCQ (Single Correct Answer)
+1
-0

If $\sinh x=\tan A$, then $|\tanh x|=$

A

$|\sin A|$

B

$|\cos A|$

C

$|\sec A|$

D

$|\operatorname{cosec} A|$

4
TS EAMCET 2022 (Online) 20th July Morning Shift
MCQ (Single Correct Answer)
+1
-0

$$ \frac{\sinh (x+y)+\sinh (x-y)}{\cosh (x+y)-\cosh (x-y)}= $$

A

$\tanh y$

B

coth $y$

C

$\tanh x \operatorname{coth} y$

D

$\tanh y \operatorname{coth} x$

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