One of the values of $(-64 i)^{5 / 6}$ is

If $\frac{(2-i) x+(1+i)}{2+i}+\frac{(1-2 i) y+(1-i)}{1+2 i}=1-2 i$, then $2 x+4 y=$

If $z=1-\sqrt{3} i$, then $z^3-3 z^2+3 z=$

The product of all the values of $(\sqrt{3}-i)^{\frac{2}{5}}$ is