1
TG EAPCET 2024 (Online) 10th May Evening Shift
MCQ (Single Correct Answer)
+1
-0
In a $\triangle A B C$, the sides $b, c$ are fixed. In measuring angle $A$, if there is an error of $\delta A$, then the percentage error in measuring the length of the side $a$ is
A
$\frac{2 \Delta \delta A}{R \sin A} \times 100$
B
$2 \times \frac{\delta A}{A} \times 100$
C
$\frac{\Delta \delta A}{2 R^{2} \sin ^{2} A} \times 100$
D
$\frac{\Delta^{2} \delta A}{R \sin A} \times 100$
2
TG EAPCET 2024 (Online) 10th May Morning Shift
MCQ (Single Correct Answer)
+1
-0
In triangle $A B C$, if $a=4, b=3$ and $c=2$, then $2(a-b \cos C)(a-c \sec B)=$
A
0
B
1
C
2
D
3
3
TG EAPCET 2024 (Online) 10th May Morning Shift
MCQ (Single Correct Answer)
+1
-0
In $\triangle A B C$, if $A=45^{\circ}, C=75^{\circ}$ and $R=\sqrt{2}$, than $r=$
A
$\frac{3+\sqrt{3}}{\sqrt{3}+\sqrt{2}+1}$
B
$\frac{\sqrt{3}+1}{\sqrt{3}+\sqrt{2}+1}$
C
$\frac{\sqrt{3}+1}{\sqrt{6}+\sqrt{3}+3}$
D
$\frac{\sqrt{3}+1}{\sqrt{3}+\sqrt{2}}$
4
TG EAPCET 2024 (Online) 10th May Morning Shift
MCQ (Single Correct Answer)
+1
-0
If $A(1,2,-3), B(2,3,-1)$ and $C(3,1,1)$ are the vertices of $\triangle A B C$, then $\left|\frac{-\cos A}{\cos B}\right|=$
A
$\frac{3 \sqrt{3}}{4 \sqrt{2}}$
B
$\frac{3 \sqrt{3}}{\sqrt{7}}$
C
$\frac{4 \sqrt{2}}{3 \sqrt{3}}$
D
$\frac{\sqrt{7}}{3 \sqrt{3}}$
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