If the tangent to $${y^2} = 4ax$$ at the point $$(a{t^2},2at)$$ where | t | > 1 is a normal to $${x^2} - {y^2} = {a^2}$$ at the point $$(a\sec \theta ,a\tan \theta )$$, then

The focus of the conic x² $$-$$ 6x + 4y + 1 = 0 is