1
WB JEE 2017
MCQ (More than One Correct Answer)
+2
-0
Change Language
If the tangent to $${y^2} = 4ax$$ at the point $$(a{t^2},2at)$$ where | t | > 1 is a normal to $${x^2} - {y^2} = {a^2}$$ at the point $$(a\sec \theta ,a\tan \theta )$$, then
A
$$t = - \cos ec\theta $$
B
$$t = - \sec \theta $$
C
$$t = 2\tan \theta $$
D
$$t = 2\cot \theta $$
2
WB JEE 2017
MCQ (More than One Correct Answer)
+2
-0
Change Language
The focus of the conic x2 $$-$$ 6x + 4y + 1 = 0 is
A
(2, 3)
B
(3, 2)
C
(3, 1)
D
(1, 4)
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