TG EAPCET 2024 (Online) 11th May Morning Shift | Permutations and Combinations Question 4 | Mathematics

If 4 letters are selected at random from the letters of the word PROBABILITY, then the probability of getting a combination of letters in which atleast one letter is repeated is

$\frac{43}{170}$

$\frac{19}{61}$

$\frac{57}{184}$

$\frac{29}{155}$

TG EAPCET 2024 (Online) 10th May Evening Shift

MCQ (Single Correct Answer)

-0

The number of ways of arranging all the letters of the word 'COMBINATIONS' around a circle so that no two vowels together is

$\frac{7!6!}{(2!)^{4}}$

$\frac{7!6!}{(2!)^{3}}$

$\frac{{ }^{8} P_{5} \times 6!}{(2!)^{3}}$

$\frac{7!x^{8} P_{5}}{(2!)^{3}}$

TG EAPCET 2024 (Online) 10th May Evening Shift

MCQ (Single Correct Answer)

-0

If all the numbers which are greater than 6000 and less than 10000 are formed with the digits, $3,5,6,7,8$ without repetition of the digits, then the difference between the number of odd numbers and the number of even number among them is

${ }^{4} P_{3}$

$3\left({ }^{4} P_{2}\right)$

${ }^{5} P_{3}$

$2\left({ }^{4} P_{3}\right)$

TG EAPCET 2024 (Online) 10th May Evening Shift

MCQ (Single Correct Answer)

-0

A man has 7 relatives, 4 of them are ladies and 3 gents; his wife has 7 other relatives, 3 of them are ladies and 4 gents. The number of ways they can invite them to a party of 3 ladies and 3 gents so that the there are 3 of man's relatives and 3 of wife's relatives, is

$341^{\circ}$

161

485

435

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