A line passing through the point of intersection of x + y = 4 and x $$-$$ y = 2 makes an angle $${\tan ^{ - 1}}\left( {{3 \over 4}} \right)$$ with the X-axis. It intersects the parabola $${y^2} = 4(x - 3)$$ at points $$({x_1},{y_1})$$ and $$({x_2},{y_2})$$, respectively. Then, $$|{x_1},{y_2}|$$ is equal to

If the vertex of the conic $${y^2} - 4y = 4x - 4a$$ always lies between the straight lines $$x + y = 3$$ and $$2x + 2y - 1 = 0$$, then

The locus of the mid-points of all chords of the parabola y² = 4ax through its vertex is another parabola with directrix