1
TG EAPCET 2024 (Online) 10th May Evening Shift
MCQ (Single Correct Answer)
+1
-0
$7 x+y-24=0$ and $x+7 y-24=0$ represent the equal sides of an isosceles triangle. If the third side passes through $(-1,1)$ then, a possible equation for the third side is
A
$3 x-y=-4$
B
$x+y=0$
C
$x-2 y=-3$
D
$3 x+y=-2$
2
TG EAPCET 2024 (Online) 10th May Evening Shift
MCQ (Single Correct Answer)
+1
-0
The combined equation of a possible pair of adjacent sides of a square with area 16 square units whose centre is the point of intresection of the lines $x+2 y-3=0$ and $2 x-y-1=0$ is
A
$(2 x-y-1+4 \sqrt{5})(x+2 y-3+4 \sqrt{5})=0$
B
$(2 x-y-1-4 \sqrt{5})(x+2 y-4 \sqrt{5})=0$
C
$(2 x-y-2 \sqrt{5})(x+2 y+2 \sqrt{5})=0$
D
$(2 x-y-1-2 \sqrt{5})(x+2 y-3+2 \sqrt{5})=0$
3
TG EAPCET 2024 (Online) 10th May Evening Shift
MCQ (Single Correct Answer)
+1
-0
If the line $2 x+b y+5=0$ forms an equilateral to triangle with $a x^{2}-96 b x y+k y^{2}=0$, then $a+3 k=$
A
$3 b$
B
192
C
$4 b^{2}$
D
102
4
TG EAPCET 2024 (Online) 10th May Morning Shift
MCQ (Single Correct Answer)
+1
-0
If the distance from a variable point $P$ to the point $(4,3)$ is equal to the perpendicular distance from $P$ to the line $x+2 y-1=0$, then the equation of the locus of the point $P$ is
A
$4 x^2+4 x y+y^2-38 x+26 y+124=0$
B
$4 x^2-4 x y+y^2-38 x-26 y+124=0$
C
$4 x^2-4 x y+y^2+38 x+26 y+124=0$
D
$4 x^2-4 x y+y^2-38 x+26 y+124=0$
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