1
MHT CET 2023 9th May Evening Shift
MCQ (Single Correct Answer)
+2
-0

The co-ordinates of the point, where the line $$\frac{x-1}{2}=\frac{y-2}{-3}=\frac{z+5}{4}$$ meets the plane $$2 x+4 y-\mathrm{z}=3$$, are

A
$$(3,-1,-1)$$
B
$$(3,1,-1)$$
C
$$(3,-1,1)$$
D
$$(-3,-1,-1)$$
2
MHT CET 2023 9th May Evening Shift
MCQ (Single Correct Answer)
+2
-0

$$\lim _\limits{x \rightarrow 0} \frac{(1-\cos 2 x) \cdot \sin 5 x}{x^2 \sin 3 x}$$ is

A
$$\frac{10}{3}$$
B
$$\frac{5}{3}$$
C
$$\frac{5}{6}$$
D
$$\frac{2}{3}$$
3
MHT CET 2023 9th May Evening Shift
MCQ (Single Correct Answer)
+2
-0

If $$\mathrm{g}$$ is the inverse of $$\mathrm{f}$$ and $$\mathrm{f}^{\prime}(x)=\frac{1}{1+x^3}$$, then $$\mathrm{g}^{\prime}(x)$$ is

A
$$\frac{1}{1+(g(x))^3}$$
B
$$1+(g(x))^3$$
C
$$\frac{g(x)}{1+(g(x))^3}$$
D
$$\frac{(\mathrm{g}(x))^3}{1+(\mathrm{g}(x))^3}$$
4
MHT CET 2023 9th May Evening Shift
MCQ (Single Correct Answer)
+2
-0

A problem in statistics is given to three students A, B and C. Their probabilities of solving the problem are $$\frac{1}{2}, \frac{1}{3}$$ and $$\frac{1}{4}$$ respectively. If all of them try independently, then the probability, that problem is solved, is

A
$$\frac{2}{3}$$
B
$$\frac{3}{4}$$
C
$$\frac{1}{3}$$
D
$$\frac{1}{4}$$
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