MHT CET 2023 9th May Evening Shift | MHT CET Year Wise Previous Years Questions

MHT CET 2023 9th May Evening Shift

MCQ (Single Correct Answer)

-0

If the mean and S.D. of the data $$3,5,7, a, b$$ are 5 and 2 respectively, then $$a$$ and $$b$$ are the roots of the equation

$$x^2-10 x+18=0$$

$$2 x^2-20 x+19=0$$

$$x^2-10 x+19=0$$

$$x^2-20 x+18=0$$

MHT CET 2023 9th May Evening Shift

MCQ (Single Correct Answer)

-0

A man takes a step forward with probability 0.4 and backwards with probability 0.6 . The probability that at the end of eleven steps, he is one step away from the starting point is

$${ }^{11} \mathrm{C}_6(0.24)^6$$

$${ }^{11} \mathrm{C}_6(0.24)^5$$

$${ }^{11} \mathrm{C}_6(0.4)^6(0.6)^5$$

$${ }^{11} \mathrm{C}_6(0.4)^5(0.6)^6$$

MHT CET 2023 9th May Evening Shift

MCQ (Single Correct Answer)

-0

If $$\mathrm{f}^{\prime}(x)=x-\frac{5}{x^5}$$ and $$\mathrm{f}(1)=4$$, then $$\mathrm{f}(x)$$ is

$$\frac{x^2}{2}+\frac{9}{4} \frac{1}{x^4}+\frac{5}{4}$$

$$\frac{x^2}{2}-\frac{5}{4} \frac{1}{x^4}+\frac{9}{4}$$

$$\frac{x^2}{2}+\frac{5}{4} \frac{1}{x^4}+\frac{9}{4}$$

$$\frac{x^2}{2}-\frac{9}{4} \frac{1}{x^4}+\frac{5}{4}$$

MHT CET 2023 9th May Evening Shift

MCQ (Single Correct Answer)

-0

A linguistic club of a certain Institute consists of 6 girls and 4 boys. A team of 4 members to be selected from this group including the selection of a Captain (from among these 4 members) for the team. If the team has to include atmost one boy, the number of ways of selecting the team is

260

320

380

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