1
MHT CET 2023 9th May Evening Shift
MCQ (Single Correct Answer)
+2
-0

The differential equation of all circles which pass through the origin and whose centres lie on $$\mathrm{Y}$$-axis is

A
$$\left(x^2-y^2\right) \frac{\mathrm{d} y}{\mathrm{~d} x}-2 x y=0$$
B
$$\left(x^2-y^2\right) \frac{\mathrm{d} y}{\mathrm{~d} x}+2 x y=0$$
C
$$\left(x^2-y^2\right) \frac{\mathrm{d} y}{\mathrm{~d} x}+x y=0$$
D
$$\left(x^2-y^2\right) \frac{\mathrm{d} y}{\mathrm{~d} x}-x y=0$$
2
MHT CET 2023 9th May Evening Shift
MCQ (Single Correct Answer)
+2
-0

If $$x^{\mathrm{k}}+y^{\mathrm{k}}=\mathrm{a}^{\mathrm{k}}(\mathrm{a}, \mathrm{k}>0)$$ and $$\frac{\mathrm{d} y}{\mathrm{~d} x}+\left(\frac{y}{x}\right)^{\frac{1}{3}}=0$$, then $$\mathrm{k}$$ has the value

A
$$\frac{1}{3}$$
B
$$\frac{2}{3}$$
C
$$\frac{1}{4}$$
D
$$\frac{2}{7}$$
3
MHT CET 2023 9th May Evening Shift
MCQ (Single Correct Answer)
+2
-0

The area (in sq. units) bounded by the curve $$y=x|x|, \mathrm{X}$$-axis and the lines $$x=-1$$ and $$x=1$$ is

A
$$\frac{2}{3}$$
B
$$\frac{1}{3}$$
C
1
D
$$\frac{4}{3}$$
4
MHT CET 2023 9th May Evening Shift
MCQ (Single Correct Answer)
+2
-0

The co-ordinates of the point, where the line $$\frac{x-1}{2}=\frac{y-2}{-3}=\frac{z+5}{4}$$ meets the plane $$2 x+4 y-\mathrm{z}=3$$, are

A
$$(3,-1,-1)$$
B
$$(3,1,-1)$$
C
$$(3,-1,1)$$
D
$$(-3,-1,-1)$$
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