GATE EE 2012 | GATE EE Year Wise Previous Years Questions

PREVIOUS NEXT

GATE EE 2012

MCQ (Single Correct Answer)

-0.6

The circuit shown is a GATE EE 2012 Analog Electronics - Feedback Amplifiers and Oscillator Circuits Question 7 English

low pass filter with $${f_{3db}} = {1 \over {\left( {{R_1} + {R_2}} \right)C}}rad/s$$

high pass filter with $${f_{3db}} = {1 \over {{R_1}C}}rad/s$$

low pass filter with $${f_{3db}} = {1 \over {{R_1}C}}rad/s$$

high pass filter with $${f_{3db}} = {1 \over {\left( {{R_1} + {R_2}} \right)C}}rad/s$$

GATE EE 2012

MCQ (Single Correct Answer)

-0.6

The feedback system shown below oscillates at $$2$$ rad/s when GATE EE 2012 Control Systems - Routh Hurwitz Stability Question 11 English

$$K=2$$ and $$a=0.75$$

$$K=3$$ and $$a=0.75$$

$$K=4$$ and $$a=0.5$$

$$K=2$$ and $$a=0.5$$

GATE EE 2012

MCQ (Single Correct Answer)

-0.3

A system with transfer function $$\,G\left( s \right) = {{\left( {{s^2} + 9} \right)\left( {s + 2} \right)} \over {\left( {s + 1} \right)\left( {s + 3} \right)\left( {s + 4} \right)}}$$ is excited by $$\sin \left( {\omega t} \right).$$ The steady-state output of the system is zero at

$$\omega = 1\,\,rad/s$$

$$\omega = 2\,\,rad/s$$

$$\omega = 3\,\,rad/s$$

$$\omega = 4\,\,rad/s$$

GATE EE 2012

MCQ (Single Correct Answer)

-0.6

The transfer function of a compensator is given as $${G_c}\left( s \right) = {{s + a} \over {s + b}}$$

$${G_c}\left( s \right)$$ is a lead compensator if

$$a = 1,b = 2$$

$$a = 3,b = 2$$

$$a = -3,b = -1$$

$$a = 3,b = 1$$

PREVIOUS NEXT

GATE EE Papers

2023