GATE EE 2012 | GATE EE Year Wise Previous Years Questions

GATE EE 2012

MCQ (Single Correct Answer)

-0.3

In the circuit shown below, the current through the inductor is GATE EE 2012 Electric Circuits - Network Theorems Question 31 English

$$\frac2{1+\mathrm j}\;\mathrm A$$

$$\frac{-1}{1+\mathrm j}\;\mathrm A$$

$$\frac1{1+\mathrm j}\;\mathrm A$$

0 A

GATE EE 2012

MCQ (Single Correct Answer)

-0.6

If $$V_A-V_B=\;6\;V$$, then $$V_C-V_D$$ is GATE EE 2012 Electric Circuits - Network Theorems Question 22 English

-5 V

2 V

3 V

6 V

GATE EE 2012

MCQ (Single Correct Answer)

-0.6

Assuming both the voltage sources are in phase, the value of R for which maximum power is transferred from circuit A to circuit B is GATE EE 2012 Electric Circuits - Network Theorems Question 21 English

GATE EE 2012 Electric Circuits - Network Theorems Question 21 English

0.8 Ω

1.4 Ω

2 Ω

2.8 Ω

GATE EE 2012

MCQ (Single Correct Answer)

-0.3

In the following figure, C₁ and C₂ are ideal capacitors. C₁ has been charged to 12 V before the ideal switch S is closed at t = 0. The current i(t) for all t is GATE EE 2012 Electric Circuits - Transient Response Question 31 English

GATE EE 2012 Electric Circuits - Transient Response Question 31 English

zero

a step function

an exponentially decaying function

an impulse function

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