WB JEE 2021 | Application of Derivatives Question 38 | Mathematics

WB JEE 2021

MCQ (Single Correct Answer)

-0.25

Two particles A and B move from rest along a straight line with constant accelerations f and f' respectively. If A takes m sec. more than that of B and describes n units more than that of B in acquiring the same velocity, then

$$(f + f'){m^2} = ff'n$$

$$(f - ff'){m^2} = ff'n$$

$$(f' - f)n = {1 \over 2}ff'{m^2}$$

$${1 \over 2}(f + f')m = ff'{n^2}$$

WB JEE 2021

MCQ (Single Correct Answer)

-0.5

If the tangent at the point P with co-ordinates (h, k) on the curve y² = 2x³ is perpendicular to the straight line 4x = 3y, then

(h, k) = (0, 0) only

(h, k) = $$\left( {{1 \over 8}, - {1 \over {16}}} \right)$$ only

(h, k) = (0, 0) or $$\left( {{1 \over 8},{1 \over {16}}} \right)$$

no such point P exists

WB JEE 2020

MCQ (Single Correct Answer)

-0.25

If the tangent to the curve y² = x³ at (m², m³) is also a normal to the curve at (m², m³), then the value of mM is

$$ - {1 \over 9}$$

$$ - {2 \over 9}$$

$$ - {1 \over 3}$$

$$ - {4 \over 9}$$

WB JEE 2020

MCQ (Single Correct Answer)

-0.25

If the function $$f(x) = 2{x^3} - 9a{x^2} + 12{a^2}x + 1$$ [a > 0] attains its maximum and minimum at p and q respectively such that p² = q, then a is equal to

$${1 \over 2}$$

$${1 \over 4}$$

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