WB JEE 2017 | Circle Question 33 | Mathematics

WB JEE 2017

MCQ (Single Correct Answer)

-0.25

The locus of the mid-points of the chords of the circle $${x^2} + {y^2} + 2x - 2y - 2 = 0$$, which make an angle of 90$$^\circ$$ at the centre is

$${x^2} + {y^2} - 2x - 2y = 0$$

$${x^2} + {y^2} - 2x + 2y = 0$$

$${x^2} + {y^2} + 2x - 2y = 0$$

$${x^2} + {y^2} + 2x - 2y-1 = 0$$

WB JEE 2017

MCQ (Single Correct Answer)

-0.5

If one of the diameters of the curve x² + y² $$-$$ 4x $$-$$ 6y + 9 = 0 is a chord of a circle with centre (1, 1), the radius of this circle is

$$\sqrt 2 $$

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