1
WB JEE 2018
+1
-0.25
The angular points of a triangle are A($$-$$ 1, $$-$$ 7), B(5, 1) and C(1, 4). The equation of the bisector of the angle $$\angle$$ABC is
A
x = 7y + 2
B
7y = x + 2
C
y = 7x + 2
D
7x = y + 2
2
WB JEE 2018
+2
-0.5
A line cuts the X-axis at A(5, 0) and the Y-axis at B(0, $$-$$3). A variable line PQ is drawn perpendicular to AB cutting the X-axis at P and the Y-axis at Q. If AQ and BP meet at R, then the locus of R is
A
$${x^2} + {y^2} - 5x + 3y = 0$$
B
$${x^2} + {y^2} + 5x + 3y = 0$$
C
$${x^2} + {y^2} + 5x - 3y = 0$$
D
$${x^2} + {y^2} - 5x - 3y = 0$$
3
WB JEE 2017
+1
-0.25
Transforming to parallel axes through a point (p, q), the equation $$2{x^2} + 3xy + 4{y^2} + x + 18y + 25 = 0$$ becomes $$2{x^2} + 3xy + 4{y^2} = 1$$. Then,
A
p = $$-$$ 2, q = 3
B
p = 2, q = $$-$$ 3
C
p = 3, q = $$-$$ 4
D
p = $$-$$ 4, q = 3
4
WB JEE 2017
+1
-0.25
Let A(2, $$-$$3) and B($$-$$ 2, 1) be two angular points of $$\Delta$$ABC. If the centroid of the triangle moves on the line 2x + 3y = 1, then the locus of the angular point C is given by
A
2x + 3y = 9
B
2x $$-$$ 3y = 9
C
3x + 2y = 5
D
3x $$-$$ 2y = 3
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