WB JEE 2010 | Quadratic Equations Question 10 | Mathematics

WB JEE 2010

MCQ (Single Correct Answer)

-0.25

The quadratic equation $${x^2} + 15|x| + 14 = 0$$ has

only positive solutions

only negative solutions

no solution

both positive and negative solution

WB JEE 2011

MCQ (Single Correct Answer)

-0.25

If sin $$\theta$$ and cos $$\theta$$ are the roots of equation ax² $$-$$ bx + c = 0, then a, b and c satisfy the relation

a² + b² + 2ac = 0

a² $$-$$ b² + 2ac = 0

a² + c² + 2ab = 0

a² $$-$$ b² $$-$$ 2ac = 0

WB JEE 2011

MCQ (Single Correct Answer)

-0.25

Let a, b, c be three real numbers such that a + 2b + 4c = 0. Then the equation ax² + bx + c = 0

has both the roots complex

has its roots lying within $$-$$1 < x < 0

has one of the roots equal to $${1 \over 2}$$

has its roots lying within 2 < x < 6

WB JEE 2011

MCQ (Single Correct Answer)

-0.25

If the ratio of the roots of the equation $$p{x^2} + qx + r = 0$$ is $$a:b$$, then $${{ab} \over {{{(a + b)}^2}}}$$ =

$${{{p^2}} \over {qr}}$$

$${{pr} \over {{q^2}}}$$

$${{{q^2}} \over {pr}}$$

$${{pq} \over {{r^2}}}$$

WB JEE Subjects