WB JEE 2009 | Application of Derivatives Question 5 | Mathematics

WB JEE 2009

MCQ (Single Correct Answer)

-0.25

The distance covered by a particle in t seconds is given by x = 3 + 8t $$-$$ 4t². After 1 second its velocity will be

0 unit/second

3 units/second

4 units/second

7 units/second

WB JEE 2009

MCQ (Single Correct Answer)

-0.25

If the rate of increase of the radius of a circle is 5 cm/sec., then the rate of increase of its area, when the radius is 20 cm, will be

10$$\pi$$

20$$\pi$$

200$$\pi$$

400$$\pi$$

WB JEE 2009

MCQ (Single Correct Answer)

-0.25

Angle between y² = x and x² = y at the origin is

$$2{\tan ^{ - 1}}\left( {{3 \over 4}} \right)$$

$${\tan ^{ - 1}}\left( {{4 \over 3}} \right)$$

$$\pi$$/2

$$\pi$$/4

WB JEE 2010

MCQ (Single Correct Answer)

-0.25

If the normal to the curve y = f(x) at the point (3, 4) makes an angle 3$$\pi$$/4 with the positive x-axis, then f'(3) is

$$-$$1

$$-$$ $${3 \over 4}$$

$${3 \over 4}$$

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