WB JEE 2008 | Straight Lines and Pair of Straight Lines Question 3 | Mathematics

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WB JEE 2008

MCQ (Single Correct Answer)

-0.25

The co-ordinates of the foot of perpendicular from (a, 0) on the line $$y = mx + {a \over m}$$ are

$$\left( {0,{a \over m}} \right)$$

$$\left( {0, - {a \over m}} \right)$$

$$\left( {{a \over m},0} \right)$$

$$\left( { - {a \over m},0} \right)$$

WB JEE 2009

MCQ (Single Correct Answer)

-0.25

If C is a point on the line segment joining A($$-$$3, 4) and B(2, 1) such that AC = 2BC, then the coordinate of C is

$$\left( {{1 \over 3},2} \right)$$

$$\left( {2,{1 \over 3}} \right)$$

(2, 7)

(7, 2)

WB JEE 2009

MCQ (Single Correct Answer)

-0.25

The coordinates of the foot of the perpendicular from (0, 0) upon the line x + y = 2 are

(2, $$-$$1)

($$-$$2, 1)

(1, 1)

(1, 2)

WB JEE 2009

MCQ (Single Correct Answer)

-0.25

A line through the point A(2, 0) which makes an angle of 30$$^\circ$$ with the positive direction of x-axis is rotated about A in clockwise direction through an angle 15$$^\circ$$. Then the equation of the straight line in the new position is

$$(2 - \sqrt 3 )x + y - 4 + 2\sqrt 3 = 0$$

$$(2 - \sqrt 3 )x - y - 4 + 2\sqrt 3 = 0$$

$$(2 - \sqrt 3 )x - y + 4 + 2\sqrt 3 = 0$$

$$(2 - \sqrt 3 )x + y + 4 + 2\sqrt 3 = 0$$

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