1
WB JEE 2009
MCQ (Single Correct Answer)
+1
-0.25

$$\tan \left[ {{\pi \over 4} + {1 \over 2}{{\cos }^{ - 1}}\left( {{a \over b}} \right)} \right] + \tan \left[ {{\pi \over 4} - {1 \over 2}{{\cos }^{ - 1}}\left( {{a \over b}} \right)} \right]$$ is equal to

A
$${{2a} \over b}$$
B
$${{2b} \over a}$$
C
$${a \over b}$$
D
$${b \over a}$$
2
WB JEE 2010
MCQ (Single Correct Answer)
+1
-0.25

Value of $${\tan ^{ - 1}}\left( {{{\sin 2 - 1} \over {\cos 2}}} \right)$$ is

A
$${\pi \over 2} - 1$$
B
$$1 - {\pi \over 4}$$
C
$$2 - {\pi \over 2}$$
D
$${\pi \over 4} - 1$$
3
WB JEE 2011
MCQ (Single Correct Answer)
+1
-0.25

The solution set of the inequation $${\cos ^{ - 1}}x < {\sin ^{ - 1}}x$$ is

A
[$$-$$1, 1]
B
$$\left[ {{1 \over {\sqrt 2 }},1} \right]$$
C
[0, 1]
D
$$\left( {{1 \over {\sqrt 2 }},1} \right]$$
4
WB JEE 2021
MCQ (Single Correct Answer)
+1
-0.25
Change Language
For $$y = {\sin ^{ - 1}}\left\{ {{{5x + 12\sqrt {1 - {x^2}} } \over {13}}} \right\};\left| x \right| \le 1$$, if $$a(1 - {x^2}){y_2} + bx{y_1} = 0$$ then (a, b) =
A
(2, 1)
B
(1, $$-$$1)
C
($$-$$1, 1)
D
(1, 2)
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