WB JEE 2009 | Trigonometric Functions & Equations Question 10 | Mathematics

WB JEE 2009

MCQ (Single Correct Answer)

-0.25

$$P = {1 \over 2}{\sin ^2}\theta + {1 \over 3}{\cos ^2}\theta $$, then

$${1 \over 3} \le P \le {1 \over 2}$$

$$P \ge {1 \over 2}$$

$$2 \le P \le 3$$

$$ - {{\sqrt {13} } \over 6} \le P \le {{\sqrt {13} } \over 6}$$

WB JEE 2009

MCQ (Single Correct Answer)

-0.25

A positive acute angle is divided into two parts whose tangents are 1/2 and 1/3. Then the angle is

$$\pi$$/4

$$\pi$$/5

$$\pi$$/3

$$\pi$$/6

WB JEE 2009

MCQ (Single Correct Answer)

-0.25

The smallest value of $$5\cos \theta + 12$$ is

WB JEE 2009

MCQ (Single Correct Answer)

-0.25

In triangle ABC, a = 2, b = 3 and sin A = 2/3, thne B is equal to

30$$^\circ$$

60$$^\circ$$

90$$^\circ$$

120$$^\circ$$

WB JEE Subjects