WB JEE 2011 | Quadratic Equations Question 12 | Mathematics

WB JEE 2011

MCQ (Single Correct Answer)

-0.25

Let a, b, c be three real numbers such that a + 2b + 4c = 0. Then the equation ax² + bx + c = 0

has both the roots complex

has its roots lying within $$-$$1 < x < 0

has one of the roots equal to $${1 \over 2}$$

has its roots lying within 2 < x < 6

WB JEE 2011

MCQ (Single Correct Answer)

-0.25

If the ratio of the roots of the equation $$p{x^2} + qx + r = 0$$ is $$a:b$$, then $${{ab} \over {{{(a + b)}^2}}}$$ =

$${{{p^2}} \over {qr}}$$

$${{pr} \over {{q^2}}}$$

$${{{q^2}} \over {pr}}$$

$${{pq} \over {{r^2}}}$$

WB JEE 2011

MCQ (Single Correct Answer)

-0.25

If $$\alpha$$ and $$\beta$$ are the roots of the equation x² + x + 1 = 0, then the equation whose roots ar $$\alpha$$¹⁹ and $$\beta$$⁷ is

x² $$-$$ x $$-$$ 1 = 0

x² $$-$$ x + 1 = 0

x² + x $$-$$ 1 = 0

x² + x + 1 = 0

WB JEE 2012

MCQ (Single Correct Answer)

-0.67

The quadratic equation 2x² $$-$$ (a³ + 8a $$-$$ 1)x + a² $$-$$ 4a = 0 possesses roots of opposite sign. Then,

a $$ \le $$ 0

0 < a < 4

4 $$ \le $$ a $$ \le $$ 8

a $$ \ge $$ 8

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