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WB JEE 2009

MCQ (Single Correct Answer)

If a = 2$$\sqrt2$$, b = 6, A = 45$$^\circ$$, then

A
no triangle is possible
B
one triangle is possible
C
two triangles are possible
D
either no triangle or two triangles are possible

Explanation

Given, a = 2$$\sqrt2$$, b = 6, A = 45$$^\circ$$

We know, $${a \over {\sin A}} = {b \over {\sin B}}$$

$${{2\sqrt 2 } \over {\sin 45^\circ }} = {6 \over {\sin B}}$$ $$\therefore$$ $$\sin B = {{6 \times {1 \over {\sqrt 2 }}} \over {2\sqrt 2 }} = {6 \over 4} = {3 \over 2}$$

Which is not possible. $$\therefore$$ No triangle is possible.

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