1
WB JEE 2023
+2
-0.5

Given $$f(x) = {e^{\sin x}} + {e^{\cos x}}$$. The global maximum value of $$f(x)$$

A
does not exist.
B
exists at a point in $$\left( {0,{\pi \over 2}} \right)$$ and its value is $$2{e^{{1 \over {\sqrt 2 }}}}$$.
C
exists at infinitely many points.
D
exists at $$x=0$$ only.
2
WB JEE 2022
+1
-0.25

A particle moving in a straight line starts from rest and the acceleration at any time t is $$a - k{t^2}$$ where a and k are positive constants. The maximum velocity attained by the particle is

A
$${2 \over 3}\sqrt {{{{a^3}} \over k}}$$
B
$${1 \over 3}\sqrt {{{{a^3}} \over k}}$$
C
$$\sqrt {{{{a^3}} \over k}}$$
D
$$2\sqrt {{{{a^3}} \over k}}$$
3
WB JEE 2021
+1
-0.25
Let f : R $$\to$$ R be such that f(0) = 0 and $$\left| {f'(x)} \right| \le 5$$ for all x. Then f(1) is in
A
(5, 6)
B
[$$-$$5, 5]
C
($$-$$ $$\infty$$, $$-$$5) $$\cup$$ (5, $$\infty$$)
D
[$$-$$4, 4]
4
WB JEE 2021
+1
-0.25
Two particles A and B move from rest along a straight line with constant accelerations f and f' respectively. If A takes m sec. more than that of B and describes n units more than that of B in acquiring the same velocity, then
A
$$(f + f'){m^2} = ff'n$$
B
$$(f - ff'){m^2} = ff'n$$
C
$$(f' - f)n = {1 \over 2}ff'{m^2}$$
D
$${1 \over 2}(f + f')m = ff'{n^2}$$
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