WB JEE 2009 | Application of Derivatives Question 7 | Mathematics

WB JEE 2009

MCQ (Single Correct Answer)

-0.25

Angle between y² = x and x² = y at the origin is

$$2{\tan ^{ - 1}}\left( {{3 \over 4}} \right)$$

$${\tan ^{ - 1}}\left( {{4 \over 3}} \right)$$

$$\pi$$/2

$$\pi$$/4

WB JEE 2010

MCQ (Single Correct Answer)

-0.25

If the normal to the curve y = f(x) at the point (3, 4) makes an angle 3$$\pi$$/4 with the positive x-axis, then f'(3) is

$$-$$1

$$-$$ $${3 \over 4}$$

$${3 \over 4}$$

WB JEE 2010

MCQ (Single Correct Answer)

-0.25

The equation of normal of $${x^2} + {y^2} - 2x + 4y - 5 = 0$$ at (2, 1) is

$$y = 3x - 5$$

$$2y = 3x - 4$$

$$y = 3x + 4$$

$$y = x + 1$$

WB JEE 2010

MCQ (Single Correct Answer)

-0.25

The point in the interval [0, 2$$\pi$$], where $$f(x) = {e^x}\sin x$$ has maximum slope, is

$$\pi$$/4

$$\pi$$/2

$$\pi$$

3$$\pi$$/2

WB JEE Subjects