1
WB JEE 2019
MCQ (Single Correct Answer)
+1
-0.25
Change Language
If $$\int {{2^{{2^x}}}.\,{2^x}dx} = A\,.\,{2^{{2^x}}} + C$$, then A is equal to
A
$${1 \over {\log 2}}$$
B
log 2
C
$${{{(\log 2)}^2}}$$
D
$${1 \over {{{(\log 2)}^2}}}$$
2
WB JEE 2018
MCQ (Single Correct Answer)
+1
-0.25
Change Language
If $$\int {{e^{\sin x}}} .\left[ {{{x{{\cos }^3}x - \sin x} \over {{{\cos }^2}x}}} \right]dx = {e^{\sin x}}f(x) + c$$, where c is constant of integration, then f(x) is equal to
A
sec x $$-$$ x
B
x $$-$$ sec x
C
tan x $$-$$ x
D
x $$-$$ tan x
3
WB JEE 2018
MCQ (Single Correct Answer)
+1
-0.25
Change Language
If $$\int {f(x)} \sin x\cos xdx = {1 \over {2({b^2} - {a^2})}}\log (f(x)) + c$$, where c is the constant of integration, then f(x) is equal to
A
$${2 \over {({b^2} - {a^2})\sin 2x}}$$
B
$${2 \over {ab\sin 2x}}$$
C
$${2 \over {({b^2} - {a^2})\cos 2x}}$$
D
$${2 \over {ab\cos 2x}}$$
4
WB JEE 2017
MCQ (Single Correct Answer)
+1
-0.25
Change Language
$$\int {\cos (\log x)dx} $$ = F(x) + C, where C is an arbitrary constant. Here, F(x) is equal to
A
$$x[\cos (\log x) + \sin (\log x)]$$
B
$$x[\cos (\log x) - \sin (\log x)]$$
C
$${x \over 2}[\cos (\log x) + \sin (\log x)]$$
D
$${x \over 2}[\cos (\log x) - \sin (\log x)]$$
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