1
WB JEE 2019
MCQ (Single Correct Answer)
+1
-0.25
Change Language
A variable line passes through the fixed point $$(\alpha ,\beta )$$. The locus of the foot of the perpendicular from the origin on the line is
A
$${x^2} + {y^2} - \alpha x - \beta y = 0$$
B
$${x^2} - {y^2} + 2\alpha x + 2\beta y = 0$$
C
$$\alpha x + \beta y \pm \sqrt {({\alpha ^2} + {\beta ^2})} = 0$$
D
$${{{x^2}} \over {{\alpha ^2}}} + {{{y^2}} \over {{\beta ^2}}} = 1$$
2
WB JEE 2019
MCQ (Single Correct Answer)
+1
-0.25
Change Language
If the point of intersection of the lines 2ax + 4ay + c = 0 and 7bx + 3by $$-$$ d = 0 lies in the 4th quadrant and is equidistant from the two axes, where a, b, c and d are non-zero numbers, then ad : bc equals to
A
2 : 3
B
2 : 1
C
1 : 1
D
3 : 2
3
WB JEE 2018
MCQ (Single Correct Answer)
+1
-0.25
Change Language
The point Q is the image of the point P(1, 5) about the line y = x and R is the image of the point Q about the line y = $$-$$ X. The circumcentre of the $$\Delta$$PQR is
A
(5, 1)
B
($$-$$ 5, 1)
C
(1, $$-$$ 5)
D
(0, 0)
4
WB JEE 2018
MCQ (Single Correct Answer)
+1
-0.25
Change Language
The angular points of a triangle are A($$-$$ 1, $$-$$ 7), B(5, 1) and C(1, 4). The equation of the bisector of the angle $$\angle $$ABC is
A
x = 7y + 2
B
7y = x + 2
C
y = 7x + 2
D
7x = y + 2
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