1
MHT CET 2025 26th April Evening Shift
MCQ (Single Correct Answer)
+2
-0

In a triangle $A B C$ with usual notations if $\angle A=30^{\circ}$, then the value of $\left(1+\frac{a}{c}+\frac{b}{c}\right)\left(1+\frac{c}{b}-\frac{a}{b}\right)=$

A

$\sqrt{3}-2$

B

$2+\sqrt{5}$

C

$\sqrt{3}+2$

D

$2-\sqrt{5}$

2
MHT CET 2025 26th April Evening Shift
MCQ (Single Correct Answer)
+2
-0

In a triangle PQR with usual notations, $\angle \mathrm{R}=\frac{\pi}{2}$. If $\tan \frac{\mathrm{P}}{2}$ and $\tan \frac{\mathrm{Q}}{2}$ are the roots of the equation $a x^2+b x+c=0(a \neq 0)$, then

A

$\mathrm{a}+\mathrm{b}=\mathrm{c}$

B

$\mathrm{b}+\mathrm{c}=\mathrm{a}$

C

$\mathrm{a}+\mathrm{c}=\mathrm{b}$

D

$\mathrm{b}=\mathrm{c}$

3
MHT CET 2025 26th April Evening Shift
MCQ (Single Correct Answer)
+2
-0

If $\cot ^{-1}(\sqrt{\cos \alpha})-\tan ^{-1}(\sqrt{\cos \alpha})=x$, then the value of $\sin x$ is

A
$\cot ^2 \frac{\alpha}{2}$
B
$\cot \frac{\alpha}{2}$
C
$\tan \frac{\alpha}{2}$
D
$\tan ^2 \frac{\alpha}{2}$
4
MHT CET 2025 26th April Evening Shift
MCQ (Single Correct Answer)
+2
-0

Considering only the principal values of the inverse trigonometric functions, the value of $\tan \left(\sin ^{-1}\left(\frac{3}{5}\right)-2 \cos ^{-1}\left(\frac{2}{\sqrt{5}}\right)\right)$ is

A

$\frac{7}{24}$

B

$\frac{-7}{24}$

C

$\frac{5}{24}$

D

$\frac{-5}{24}$

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