1
MHT CET 2025 26th April Evening Shift
MCQ (Single Correct Answer)
+1
-0

Lorentz magnetic force is acting on a particle of charge q moving with velocity $\vec{V}$ in a magnetic field $\vec{B}$. The work done by this force on the charged particle is

A

zero

B

one

C

infinity

D

$\mathrm{qB} \sin \theta$

2
MHT CET 2025 26th April Evening Shift
MCQ (Single Correct Answer)
+1
-0

Graph shows the variation of fringe width ( X ) versus distance of the screen from the plane of the slits (D) in Young's double slit experiment. (keeping other parameters same, $d=$ distance between the slits). The wavelength of light used can be calculated as

A

slope $\times \mathrm{d}^2$

B

$\frac{\mathrm{d}}{\text { slope }}$

C

$\frac{\text { slope }}{\mathrm{d}}$

D

slope $\times \mathrm{d}$

3
MHT CET 2025 26th April Evening Shift
MCQ (Single Correct Answer)
+1
-0

The point charges $+\mathrm{q},-\mathrm{q},-\mathrm{q},+\mathrm{q},+\mathrm{Q}$ and -q are placed at the vertices of a regular hexagon ABCDEF as shown in figure. The electric field at the centre of hexagon ' $O$ ' due to the five charges at $\mathrm{A}, \mathrm{B}, \mathrm{C}, \mathrm{D}$ and F is twice the electric field at centre ' O ' due to charge +Q at E alone. The value of $Q$ is

A

$\frac{\mathrm{q}}{2}$

B

q

C

$2 q$

D

$4 q$

4
MHT CET 2025 26th April Evening Shift
MCQ (Single Correct Answer)
+1
-0

$$ \text { The frequency at resonance for the circuit is } $$

A

$\frac{1}{4 \pi \sqrt{\mathrm{LC}}}$

B

$\frac{1}{2 \pi \sqrt{\mathrm{LC}}}$

C

$\frac{1}{\pi \sqrt{\mathrm{LC}}}$

D

$\frac{2}{\pi \sqrt{\mathrm{LC}}}$

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