MHT CET 2025 23rd April Morning Shift | MHT CET Year Wise Previous Years Questions

MHT CET 2025 23rd April Morning Shift

MCQ (Single Correct Answer)

-0

The differential equation of all circles touching the Y -axis at the origin and centre on the X -axis is

$x^2+y^2+2 x y \frac{\mathrm{~d} y}{\mathrm{~d} x}=0$

$x^2-y^2+2 x y \frac{\mathrm{~d} y}{\mathrm{~d} x}=0$

$2 x^2+y^2+x y \frac{\mathrm{~d} y}{\mathrm{~d} x}=0$

$x^2-2 y^2+2 x y \frac{\mathrm{~d} y}{\mathrm{~d} x}=0$

MHT CET 2025 23rd April Morning Shift

MCQ (Single Correct Answer)

-0

The area bounded by the curve $x^2=8 y$ and the straight line $x-8 y+2=0$ is

$\frac{9}{8}$ sq. units

$\frac{15}{16}$ sq. units

$\frac{9}{16}$ sq. units

$\frac{15}{8}$ sq. units

MHT CET 2025 23rd April Morning Shift

MCQ (Single Correct Answer)

-0

In a triangle ABC with usual notations, $\cot \frac{\mathrm{A}}{2}+\cot \frac{\mathrm{B}}{2}+\cot \frac{\mathrm{C}}{2}=$

$\frac{\mathrm{s}^2}{\Delta}$, where $\Delta$ is the area of the triangle ABC .

$\frac{s}{\Delta}$, where $\Delta$ is the area of the triangle ABC .

$\frac{\Delta}{\mathrm{s}}$, where $\Delta$ is the area of the triangle ABC .

$\Delta$, where $\Delta$ is the area of the triangle ABC .

MHT CET 2025 23rd April Morning Shift

MCQ (Single Correct Answer)

-0

The area of the rectangle having vertices $\mathrm{P}, \quad \mathrm{Q}, \quad \mathrm{R}, \quad \mathrm{S}$ with position vectors $-\hat{\mathrm{i}}+\hat{\mathrm{j}}+\hat{\mathrm{k}}, \hat{\mathrm{i}}+\hat{\mathrm{j}}+\hat{\mathrm{k}}, \hat{\mathrm{i}}-\hat{\mathrm{j}}+\hat{\mathrm{k}},-\hat{\mathrm{i}}-\hat{\mathrm{j}}+\hat{\mathrm{k}}$ respectively is

1 square unit

2 square units

3 square units

4 square units

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